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#1
November 1st, 2004, 07:23 AM
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shell scripting
hi guys. I am trying to write a small shell script which reads an input file and filters out anything that is between (// and new line) and between (*/ and /*) basically c comments. Also I am trying to count the number of "(" and ")" when encountered in the file.
I am trying to use AWK filter to accomplish this. I can use SED, Grep or any other filter if needed. awk <search pattern> {<program actions>} Any help would be greatly appreciated. Thanks, Arun
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#2
November 2nd, 2004, 04:02 AM
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between (// and new line) and between (*/ and /*)
(you sure mean: /* and */) the fastest way doing that is sed sed '/\/\/.*/d;/\*\/,/\/\*/d' a probl, this will delete /* ... */ AND the legal, possible and worst write style: abc(); /*... ... ...*/ cba(); to work on this with regexpr is a big job. the second Q: count '()' is less trivial. sed is not appropriate (nota: no probls IF you COMMAND sed) awk has sure a lot of functs able for that, but slow grep can only add lines, so: xx() AND xx(); yy(); always gives 1 a combination of: sed, awk is possible, but less interesting perl may be a good alternative at least your friend is: a (very) simple 20 line c
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#3
November 2nd, 2004, 09:09 AM
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Quote:
hi, thanks for the help. You are right it should be /*...*/ I can't use peral, so I have to use awk or grep. Could u pls give me an example on how to count the number of left paran and right paran. Thanks a bunch
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#4
November 2nd, 2004, 10:14 AM
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grep is useless, and
it's a long way using awk why do you insist with them ? the reasonable way is c: Code:
register int left, right;
char buf[MaxBuf], *pointer;
FILE *fd;
/*
open the file, and check, then
*/
if(!(fd = fopen("filename","r"))) exit(1);
left = right = 0;
while(fgets(buf,sizeof(buf),fd)
for(pointer = buf; *pointer; ++pointer){
if(*pointer == '(') ++left;
if(*pointer == ')') ++right;
}
fclose(fd);
printf("left = %d right = %d\n",left,right);
exit(0);
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