unable to see the ps -ef full details

I am unable to see the command in ps -ef output. The last colomn of the ps -ef output consisting of the command is truncated. I need the full path of the process command. is there any way to acheive this
Thank you
Shameem S

I usually do a:

# export COLUMNS=1000
# ps -ef|less
(less will let you scroll horizontally then )

but if this works will depend on your specific versions of UNIX, "less" and "ps".

hth,
M.

This might work, depending on unix flavor:

ps -ef | fold

Will wrap long lines to next line.

If you are using solaris try /usr/ucb/ps -auxwww instead of ps -ef

it doesn't truncate the output like ps does.

Hey I got this with the help of /usr/ucb/ps -auxww. That made my life easier. Thank you.

One more small help needed. I want to cut any one field ( I mean column) from the output of /usr/ucb/ps -auxww. I am unable to find the field separator to use "cut" command. can any body help me out to solve this. Thank you
Shameem S

FOr .e.g.
I have the total output as follows
root 1695 2.3 0.2 4008 2936 ? S 13:32:41 0:01 /opt/opendeploy/bin/iwdeploy -fs /opt/opendeploy/conf/branches/SolarisFarm/content/technology/governance/iw.odclient.cfg -V 1 staging-to-s0056pdv

Now I want to cut the parts
SolarisFarm/content/technology/governance and
staging-to-s0056pdv

Please let me know...