Unix script help

Hi

I am trying to write a script that will delete all the files that haven't been modified in 30 days or more. I have got this working fine ... The problem is that there is a directory called 'reports' that can't be touched. example...

This will delete everything... Since the variable $line is a full path, I can't even check to see if I am in the reports directory (Or I don't know how to I should say)

So my question is this...
Does any one know how to write an IF Statement in a unix script that will check if the string '/reports/' is in the variable $line??

Thanks...
Or if there is an easier way to do this, I am open to any suggestions...

Thanks to anyone who has taken the time to look at this, but I have found a work around for my problem...

Here it is...

So basically I am checking what is returned from the grep, and if it is a 0 length string then it did not find the word /reports/ and therefor the file cannot be in the reports directory.

I am still open to suggestion however if anyone has a better/easier solution to this problem

Thanks for your time...

can we try to write unix ?

for line in `find WHATYOUWANT -mtime +$1`
do
case $line in exception0) continue
;; execption1) continue
;; execption2) continue
;; execptionxxxxx) continue
;; esac
rm -f $line
done


chage exception by what your exceptions

I don't get it...
was my code wrong, or is this just a more efficient way of doing it?

no your code isnt wrong, just no code.
i would try: find ¦ egrep -v what-you-dont-want-kill ¦ xargs rm

back to your script

why set a variable catching the output of echo¦ grep
to get the filename of the file you are working on ?

why test the output of grep that way ?

echo xxx¦grep -s x >/dev/null
gives 0 (x founded) 1 (not found)

read a little man pages