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#1
October 5th, 2003, 12:15 PM
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using grep to find and not find strings
I'm trying to search php files in a directory for their include files except those that have the strings "header" or "footer".
This is what I'm using so far with no luck: grep -Ers '((include|require)_once|include|include_files).*[^(footer|header)].*' directory_name I guess my question is how do I use the ^ to do a no match on strings. I can't seem to find the right documentation or examples anywhere. I'm using GNU grep version 2.4.2...Please help. Thanks.
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#2
October 5th, 2003, 12:29 PM
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I would do it in two steps:
1. find all includes 2. remove the headers and footers. Code:
grep -Eir . 'include(_files)?|require(_once)?' | grep -viE 'header|footer' ... adjust to your needs  ("grep -v" is find "not") hth, M.
__________________
-- Manuel Hirsch - Linux, FreeBSD, programming, administration articles, tutorials and more.
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#3
October 5th, 2003, 01:13 PM
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aahhhh
brilliant. thanks!
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