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  #1  
Old July 6th, 2004, 11:14 PM
chess chess is offline
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Validating integer input

Hi,
Can anyone tell me how can I validate an input as Integer not character or anything else??? Is there any way to read the input without the user hitting the <Enter> key?? I really appreciate your help.

Thanx

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  #2  
Old July 7th, 2004, 03:55 AM
murugesan murugesan is offline
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This will do

Code:
#!/bin/sh
getkey  2>/dev/null 1>/dev/null
KEY=`echo $?`
case $KEY in
        48)
                echo "0";;
        49)
                echo "1";;
        50)
                echo "2";;
        51)
                echo "3";;
        52)
                echo "4";;
        53)
                echo "5";;
        54)
                echo "6";;
        55)
                echo "7";;
        56)
                echo "8";;
        57)
                echo "9";;
esac

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  #3  
Old July 7th, 2004, 09:28 AM
jim mcnamara jim mcnamara is offline
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What is getkey? It's definitely not part of the Bourne shell.

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  #4  
Old July 8th, 2004, 07:57 PM
chess chess is offline
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I tried your code but doesn't seem to work though. The KEY variable is always set to 0. I put a sleep so it can wait for the user to input. Don't know whether thats the problem. Can you please help me mate.

#!/bin/sh

while [ true ]; do
sleep 2
getkey 2>/dev/null 1>/dev/null
KEY=`echo $?`
echo $?
case $KEY in
48)
echo "0";;
49)
echo "1";;
50)
echo "2";;
51)
echo "3";;
52)
echo "4";;
53)
echo "5";;
54)
echo "6";;
55)
echo "7";;
56)
echo "8";;
57)
echo "9";;
esac
done

Thanx..

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  #5  
Old July 8th, 2004, 10:57 PM
murugesan murugesan is offline
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Sorry I missed a function there.
Code:
function getkey() 
{ 
     read -rsn  1 REPLY; 
     return $REPLY;
}
Also change the numbers from 48 - 57
as
0-9 
Coded it in C mood :-)

Last edited by murugesan : July 8th, 2004 at 11:15 PM.

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