[yogi27]

Hi,

I am getting the value of $var by: $var = substr($addr,0,1);

And depending on length of $var, I do some processing:

if ($#var == 1) {
....................
} elsif ($#var == 2) {
....................
}

But, I never go into this if condition even if $var = 7.

Can someone help me with this. Thanks.

-Yogesh.

[guggach]

yogi27
- may i kindly ask you for a little more precision, what do you want?
- read your code

i am not a perl specialist, i just use use it
the statement: $var = substr($addr,0,1);
IMO, assign to $var the value of $addr starting by pos 0 ending by pos 1
so if $addr is not empty, $var will always be the first char of $addr w/ length == 1

perl sure knows a function (maybe) length() to compute a string length
also: $mylen = length($var);

what are you checking here: if ($#var == 1)
NO SENSE for me.

[yogi27]

This is what I want:

If the length of the variable is 1, I'll append it by 2 zeros. If the length of the variable is 2, I'll append it by 1 zero. If the length of the variable is 3, I'll append it by 0 zeros.

I want to get the value in 3 digits.

Thanks,
Yogesh.

[guggach]

you are not clear, whats means
>>> If the length of the variable is 1, I'll append it by 2 zeros....
a) var=a; do you want: a00(this appends) or 00a(this inserts) ?
b) is var an int or char ?
c) man pages: printf