Visual Basic Programming
 
Forums: » Register « |  User CP |  Games |  Calendar |  Members |  FAQs |  Sitemap |  Support | 
User Name:
Password:
Remember me

The Shed is going Social! Join us on FaceBook and Twitter and chime in on the conversation.

Go Back   Dev Shed ForumsProgramming Languages - MoreVisual Basic Programming

Reply
Add This Thread To:
  Del.icio.us   Digg   Google   Spurl   Blink   Furl   Simpy   Y! MyWeb 
Thread Tools Search this Thread Rate Thread Display Modes
 
Unread Dev Shed Forums Sponsor:
  #1  
Old October 29th, 2012, 09:09 PM
huyvu90 huyvu90 is offline
Registered User
Dev Shed Newbie (0 - 499 posts)
 
Join Date: Oct 2012
Posts: 2 huyvu90 User rank is Just a Lowly Private (1 - 20 Reputation Level) 
Time spent in forums: 22 m 59 sec
Reputation Power: 0
Algorithm help.

Let say I have an array with the following numbers:

1,4,12,22,53,51,49,55,2,5,50,51,100


I'm trying to develop an algorithm that finds the max number of consecutive number in the array that is between 40 and 60.

For the example above, the algorithm should return 53,51,49 and 55. 50,51 are not returned because that is only 2 consective number that is between 40 and 60.

Reply With Quote
  #2  
Old November 25th, 2012, 10:01 PM
argee argee is offline
Registered User
Dev Shed Newbie (0 - 499 posts)
 
Join Date: Nov 2012
Posts: 8 argee User rank is Corporal (100 - 500 Reputation Level)argee User rank is Corporal (100 - 500 Reputation Level)argee User rank is Corporal (100 - 500 Reputation Level)argee User rank is Corporal (100 - 500 Reputation Level) 
Time spent in forums: 3 h 19 m 29 sec
Reputation Power: 0
Hi huyvu90,

Unless I'm misunderstanding, I think this should do what you want:

Code:
Dim ArNums() As Integer
Dim i As Integer, j As Integer
Dim savej As Integer

'....code to load numbers into array ArNums
    
     For i = 0 To UBound(ArNums)
        If ArNums(i) > 40 And ArNums(i) < 60 Then
            j = j + 1
            If j > savej Then
                savej = j
            End If
        Else
            j = 0
        End If
    Next i

    MsgBox savej          '<----- this should be your answer
                                ' ('4' for your example)


cheers,

argee

Reply With Quote
  #3  
Old January 1st, 2013, 04:09 AM
Incidentals Incidentals is offline
Contributing User
Dev Shed Newbie (0 - 499 posts)
 
Join Date: Nov 2010
Posts: 89 Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level) 
Time spent in forums: 1 Day 4 h 23 m 19 sec
Reputation Power: 156
Quote:
Originally Posted by argee
Hi huyvu90,

Unless I'm misunderstanding, I think this should do what you want:

Code:
Dim ArNums() As Integer
Dim i As Integer, j As Integer
Dim savej As Integer

'....code to load numbers into array ArNums
    
     For i = 0 To UBound(ArNums)
        If ArNums(i) > 40 And ArNums(i) < 60 Then
            j = j + 1
            If j > savej Then
                savej = j
            End If
        Else
            j = 0
        End If
    Next i

    MsgBox savej          '<----- this should be your answer
                                ' ('4' for your example)


cheers,

argee


you missed the point!

you have coded for an algorythm that returns the number of 40 to 60 values and not considered the consecutive part of the question

the looping is fine but you need to be looking ahead and you need to be flagging the count-now nature of the problem

try walking through the array with 2 pointers if and only if they both point to values in the range should you show them and remember to indicate that a match has ben found. Using the match you will be able to deduce that the first pointer is pointing at a valid entry when the pointers no longer have values in range and at that point you should reset the flag and output the first pointed to value.

hope that explains what to do

code available if needed

Reply With Quote
  #4  
Old January 1st, 2013, 12:30 PM
argee argee is offline
Registered User
Dev Shed Newbie (0 - 499 posts)
 
Join Date: Nov 2012
Posts: 8 argee User rank is Corporal (100 - 500 Reputation Level)argee User rank is Corporal (100 - 500 Reputation Level)argee User rank is Corporal (100 - 500 Reputation Level)argee User rank is Corporal (100 - 500 Reputation Level) 
Time spent in forums: 3 h 19 m 29 sec
Reputation Power: 0
I am allowing for the consecutive part of the problem.

That's why the loop resets the value of j to 0 if a match is not found, because then the matches are no longer consecutive.

The number of consecutive matches is stored in "savej" only if it exceeds any previously stored value in "savej".

I had considered afterwards that, although they initially said they wanted the maximum number of values, the OP may have wanted the actual consecutive number group returned, not just the count of them. The code could be modified like this :

Code:
Dim intStartPos As Integer
Dim strResult As String

'...code to load numbers into array ArNums
    
    For i = 0 To UBound(ArNums)
        If ArNums(i) > 40 And ArNums(i) < 60 Then
            j = j + 1
            If j > savej Then
                savej = j
                intStartPos = i - j
            End If
        Else
            j = 0
        End If
    Next i

    For i = (intStartPos + 1) To (intStartPos + savej)
        strResult = strResult & ArNums(i) & ","
    Next i

    Debug.Print strResult       'contains the consecutive matches separated by commas


In any case, this thread is aging and the original poster has not returned it seems.

Reply With Quote
  #5  
Old January 1st, 2013, 04:51 PM
Incidentals Incidentals is offline
Contributing User
Dev Shed Newbie (0 - 499 posts)
 
Join Date: Nov 2010
Posts: 89 Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level)Incidentals User rank is First Lieutenant (10000 - 20000 Reputation Level) 
Time spent in forums: 1 Day 4 h 23 m 19 sec
Reputation Power: 156
nicely done

I didnt complete my writeup, but its nice to see you did - well done, and the explaination will help others understand your process better.

Reply With Quote
  #6  
Old February 9th, 2013, 04:36 PM
GGriggs GGriggs is offline
Registered User
Dev Shed Newbie (0 - 499 posts)
 
Join Date: Feb 2013
Posts: 18 GGriggs User rank is Just a Lowly Private (1 - 20 Reputation Level) 
Time spent in forums: 4 h 45 m 43 sec
Reputation Power: 0
algorythm

the main power of VBA is to use it with excel to do the serious number crunching

Your problem is quite hard in vba but very easy in excel

use VBA to load input and extract and display answers and excel to crunch the numbers

i can't attach for some reason but i have written a spreadsheet to crack it in about 2 mins

email me at graham.griggs@tiscali.co.uk and i will send you a copy

Reply With Quote
Reply

Viewing: Dev Shed ForumsProgramming Languages - MoreVisual Basic Programming > Algorithm help.

Developer Shed Advertisers and Affiliates



Thread Tools  Search this Thread 
Search this Thread:

Advanced Search
Display Modes  Rate This Thread 
Rate This Thread:


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
View Your Warnings | New Posts | Latest News | Latest Threads | Shoutbox
Forum Jump

Forums: » Register « |  User CP |  Games |  Calendar |  Members |  FAQs |  Sitemap |  Support | 
  
 


Powered by: vBulletin Version 3.0.5
Copyright ©2000 - 2013, Jelsoft Enterprises Ltd.

© 2003-2013 by Developer Shed. All rights reserved. DS Cluster - Follow our Sitemap