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X installs Y. Y installs X. Possible?

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X installs Y. Y installs X. Possible? Visual Basic Programming forum discussing VB specific programming information. Quickly prototype and build applications with this robust and simple language.

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  #1  
Old February 9th, 2006, 05:50 PM
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X installs Y. Y installs X. Possible?
Program x must be able to install program y. Program y must be able to install program x. Each of these programs must do more than install eachother of course, but this is where I am running into some difficulty. I havn't written any code yet so there is nothing to show, I just want to know if it is possible first. Anyways... I must be overlooking something... Thanks in advance...
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Old February 9th, 2006, 05:54 PM
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Quote:
I must be overlooking something...


Not you, I think it's me ... I can't seem to find the VB related question in your post. :\
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Old February 9th, 2006, 06:02 PM
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It is not vb related. It is a general programming logic question. However I am making it in vb.
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Old February 9th, 2006, 06:52 PM
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Sounds to me you're tryin to create a shadey program there.
Making a fault-tolerant malware?
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Old February 10th, 2006, 08:59 AM
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But you'll need something to install the first one, before it can start installing the others...then you'll need something to install THAT one so it can install the first one...sort of an endless loop, no?
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Old February 10th, 2006, 10:45 AM
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I know it is some sort of endless loop. But I also know it can be done... Somehow... Perhaps if the programs installed eachother via the internet... But that seriously infringes on the programs' versatility. Is there any other way? Without using the internet that is. And yes the first program is installed by another program.
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Old February 10th, 2006, 12:43 PM
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I don't think anyone will directly help you about this. Maybe provide reasoning behind why you need this or want this. Maybe then someone will help you via PM.
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Old February 10th, 2006, 02:40 PM
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This sounds dumb....why would you want to do this? If you're going to have a program to install other programs, just install the programs manually and be done with it...


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Old February 10th, 2006, 04:48 PM
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I could think of a valid reason for such fault tolernance. Not really great reason, but(and don't use this as an excuse to get an answer) you /could/ say it's a rather poor type of protection from executeable infective virii. The fault tolerance installing between the two processes could be governed by a function that runs a checksum on the file, it checks this sum against a stored checksum, if it's not the same, the executeable file gets replaced.
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