1 XSL file, 2 XML docs?

This may seem silly, but I'd like to use one XSL stylesheet and reference 2 different XML documents. Is this possible? The output will be HTML, I have a table where 1 cell has data from one XML doc and the other cell has data from a different XML doc.

You can use the xsl:document() function to access nodes
in an external XML document.

Here is a working example:

-------- a.xml --------
<?xml version="1.0" encoding="iso-8859-1"?>
<root>
<entry>
<day>mon</day>
<amount>34</amount>
<amount>43</amount>
</entry>
</root>

-------- b.xml --------
<?xml version="1.0" encoding="iso-8859-1"?>
<root>
<entry>
<day>mon</day>
<amount>12</amount>
<amount>13</amount>
</entry>
</root>

-------- a.xsl ---------
<?xml version="1.0" encoding="ISO-8859-1" ?>

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output method="html" />

<xsl:variable name="a" select="/"/>

<xsl:template match="/">
<xsl:for-each select="document('./b.xml')//entry" >
<xsl:value-of select="day" />
<xsl:text>: </xsl:text>
<!-- note the context! Currently document b -->
<xsl:value-of select="sum(//amount)" />
<xsl:text>, </xsl:text>
<xsl:value-of select="sum($a//amount)" />
</xsl:for-each>
</xsl:template>

</xsl:stylesheet>

Thanks! Quick question:

document('./b.xml')

That means that b.xml would be in the same folder as a.xml and the stylesheet, right?

Can I put an absolute path in there, like

C:/XML/blah/b.xml

?