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#1
July 17th, 2003, 05:12 PM
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basic xslt : nodename and nodevalue
How to get the node name and node value of an xml using xslt with out hard coding the node name?
<table> <row> <name>one</name> <id>26</id> <rownum>9876</rownum> </row> <row> <name>two</name> <id>26</id> <rownum>9875</rownum> </row> </table> i want the following format from the above xml, nodename nodevalue table --- row --- name one id 26 rownum 9876 row --- name two id 26 rownum 9875 Regards, PLR.Kannan Last edited by plrkannan : July 17th, 2003 at 05:15 PM.
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#2
July 18th, 2003, 02:21 AM
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If you dont't want to use the names I guess you have to use the position of the element in the tree.
Something like: Code:
<xsl:value-of select="name(/*[1])"/> <xsl:value-of select="/*[1]"/> <xsl:value-of select="name(/*[1]/*[1])"/> <xsl:value-of select="/*[1]/*[1]"/> <xsl:value-of select="name(/*[1]/*[2])"/> <xsl:value-of select="/*[1]/*[2]"/> ... Perhaps this will help you
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