desperately need help with date sorting in XSL!!

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November 6th, 2003, 08:05 PM

yguo080

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Join Date: Nov 2003

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desperately need help with date sorting in XSL!!

I'm doing an assignment.

I'm a beginner in all things XML related and I need to know how to sort by date. My formatting is:

DD-MM-YY

but I don't know how to sort. First of all, in the DTD file, the date is regarded as #PCDATA.

And I have no idea how to sort it by year, then month, then day.

If my problem is too vague for you, could you give me some clues on where I can go to find additional information on sorting dates? Thanks.

November 7th, 2003, 01:20 PM

teedee

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Code:

<xsl:for-each select="Date">
<xsl:sort select="substring(. , 7,2)" order="ascending" data-type="number"/>
<xsl:sort select="substring(. , 4,2)" order="ascending" data-type="number"/>
<xsl:sort select="substring(. , 1,2)" order="ascending" data-type="number"/>
<xsl:value-of select="."/><br/>
</xsl:for-each>

March 3rd, 2004, 01:00 PM

khwang

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Location: Babylon 4

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I have a question about the following code:

Quote:

Originally Posted by teedee

Code:

<xsl:for-each select="Date">
<xsl:sort select="substring(. , 7,2)" order="ascending" data-type="number"/>
<xsl:sort select="substring(. , 4,2)" order="ascending" data-type="number"/>
<xsl:sort select="substring(. , 1,2)" order="ascending" data-type="number"/>
<xsl:value-of select="."/><br/>
</xsl:for-each>

I currently use the above format, but each xsl:sort tag is self-standing. Shouldn't they be nested? example:

Code:


<xsl:sort select="substring(. , 7,2)" order="ascending" data-type="number">
<xsl:sort select="substring(. , 4,2)" order="ascending" data-type="number">
<xsl:sort select="substring(. , 1,2)" order="ascending" data-type="number">
</xsl:sort></xsl:sort></xsl:sort>

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