Finding the first node in a group in xsl

Hi,

I have a file with glossary items that I need to split alphabetically. This is working by just sorting the list, but now I need to add a header above each group of letters, eg the whole group of A entries has a header called 'A entries' above it etc.

Here is the xsl code (just for letter b):

<xsl:template match="finalGlossary">
<xsl:for-each select="hotWord">
<xsl:sort select="hotWordTitle"/>
<p>
<xsl:call-template name="alphaB"/>
<xsl:apply-templates select="hotWordTitle"/>
<xsl:apply-templates select="hotWordTxt"/>
</p>
<p>[<a href="#top">Top</a>]</p>
</xsl:for-each>
</xsl:template>

<xsl:template name="alphaB">
<xsl:if test="hotWordTitle[starts-with(text(),'B')]">
<span class="b">B Entries</span><br/><br/>
</xsl:if>
</xsl:template>

<xsl:template match="hotWordTitle">
<span class="b"><xsl:apply-templates/></span><br/>
</xsl:template>

<xsl:template match="hotWordTxt">
<xsl:apply-templates/>
</xsl:template>

<xsl:template match="hotWordBold">
<span class="b"><xsl:apply-templates/></span>
</xsl:template>

The problem is that it puts 'B entries' above each of the items starting with b! The only way that I seem to be able to select the first entry is by checking the position() and then adding an if statement in the alphaB template.

As hardcoding doesn't seem a logical thing to do, is there any way to check which the first entry of a particular letter is, so that only the first item in the group has the header above it?

Thank you