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Old June 23rd, 2004, 09:22 AM
mxpt3c mxpt3c is offline
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Question Help needed... can't get XSL:IF to do what I want!

...and not only that there isn't a single helpful page on the internet, at least not for what I'm trying to do. Probably because it's impossible or something, but I'll give it a try here just in case. Basically what I would like to do is use xsl:if to test IF the the contents of one tag includes another tag. Can I do this? Can I have something like

<xml1>
<datatype>
<integer>1</integer>
</datatype>
</xml1>

and

<xml2>
<datatype>
<nominal>'A' means 'Awesome'</nominal>
</datatype>
</xml2>

What I want to do when prompted with pieces of code in this example is, check IF the <datatype> tag contains a tag entitled <nominal> or <integer>, and then output a certain value based on IF it is nominal. I don't particularly care about the data in <nominal> and <integer> in this case, I just need to know which tag is present. Is there any way at all to do this? I'd greatly appreciate any help I can get, thanks a lot in advance!!!

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Old June 23rd, 2004, 03:09 PM
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How about checking to see if its a number, if its a number print using select integer, else select nominal ???
Quote:


How to check that the content of an element is numeric
David Carlisle

<xsl:template match="a">
<xsl:value-of select="."/>
<xsl:if
test= "string(number(.))='NaN'">
is not a number</xsl:if>
</xsl:template>
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