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#1
July 21st, 2004, 09:30 PM
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[Help] XML transform with sorting
Input.xml
Code:
<employees> <employee id="1" name="Tom" salary="5000"></employee> <employee id="2" name="Michelle" salary="4800"></employee> <employee id="3" name="Samuel" salary="7000"></employee> </employees> My desired output (output.xml) Code:
<staffs> 1. Samuel 7000 2. Tom 5000 3. Michelle 4800 </staffs> How to write my XSL so that it transforms as I want? Note that the output is <auto number increase><name><salary> all located in one element node. The output requirement/format is fixed ! 
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#2
July 22nd, 2004, 10:34 AM
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#3
July 30th, 2004, 04:51 PM
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Sorting
use this:
<xsl:for-each select="employees/employee"> <xsl:sort select="@salary" data-type="number" order="descending"/> <xsl:value-of select="position()"/>.<xsl:value-of select="@name"/>*<xsl:value-of select="@salary"/> </xsl:for-each> -- Murugesan M  ******************************************* Quote:
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