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#1
July 22nd, 2003, 01:01 PM
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How to create an xsl internal template match
I want to out put this html via my xsl everytime and there is no <element> reference in the xml page. I just want to display this button when this xsl page is transformed. How do i do this without using a template match (since there is no match) or how would i create an internal match inside the xsl?
Code:
<table cellPadding="2" cellSpacing="1" border="0">
<tr>
<form name="redirectMe">
<td align="right">
<input type="button" value="Exit Course" onClick="javascript:document.location.href='{@href}'" id="button1" name="button1"/>
</td>
</form>
</tr>
</table>
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#2
July 30th, 2003, 12:23 AM
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Put your code in a separate page and call it via the <xsl:copy-of> element:
<xsl:copy-of select="document('http://www.yourdomain.com/yourfile.html')"/> If your webserver supports server-side includes, you could also use the <xsl:comment> element to insert an SSI.
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