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#1
August 5th, 2003, 09:21 AM
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hyperlinking for each node() using xsl:value + .xml extention of exsisting file
Ok, the subject is pretty messy, i know.
I am trying to loop through all instances of a tag and hyperlink the string in the table cell with the matching .xml file in the directory. so if string 'radostan' appears in the table cell and there is a file called 'radostan.xml' a hyperlink appears for this instance. Does anyone know what the <a href=" ></a> should be? Thanks in advance radostan
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#2
August 5th, 2003, 12:59 PM
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Can we see the relevant portion of your XML file and the XSL you're trying?
__________________
# Jeremy Explain your problem instead of asking how to do what you decided was the solution.
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#3
August 5th, 2003, 01:16 PM
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figured it out
the code is the following. <a class="sub_nav_links"><xsl:attribute name="href"><xsl:value-of select="node()"/>.xml</xsl:attribute><xsl:value-of select="node()"/></a>
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