Passing parameter via urlquery / pure xml/xslt

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February 5th, 2013, 10:11 AM

silver_fern

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Passing parameter via urlquery / pure xml/xslt

Hi experts,

I am quite new to xml/xslt programming...

I am using pure xml/xslt (no java, no php...) and want to pass a parameter value from xml to the xslt file.
I tried to do this via a urlquery in the xml file

Code:

 <a>           
 <xsl:attribute name="href">
./myfile.xml?myparam=value  </xsl:attribute>
click here
</a>

and tried to get the value within the xslt file with

Code:

<?xml version="1.0" encoding="utf-8"?>

<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:param name=myparam/> 

<xsl:template match="/">
    <html>
      <body>
          <p>
          <xsl:value-of select="$myparam" />
          </p>
      </body>
     </html>
  </xsl:template>
</xsl:stylesheet>

However, I could not obtain the value - myparam appears empty.

Can such an approach work at all if no "wrapping" language is used?

Cheers
Silver fern

P.S.: And sorry, if that is a very stupid question...

February 5th, 2013, 02:13 PM

requinix

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Quote:

Originally Posted by silver_fern

I tried to do this via a urlquery in the xml file

Code:

 <a>           
 <xsl:attribute name="href">
./myfile.xml?myparam=value  </xsl:attribute>
click here
</a>

That doesn't make sense. You have some <a> in the XML, using an XSLT attribute, to link to itself with a query string?

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