problem with xslt

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April 17th, 2004, 04:36 PM

vithal_raja

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Join Date: Apr 2004

Posts: 1

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problem with xslt

hi
i'm using a small java servlet that would take rss feeds(right now 2) as inputs and produce html page when given a xsl file.....

the servlet prgm is something like this

import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.net.URL;

import javax.xml.transform.TransformerFactory;
import javax.xml.transform.Transformer;
import javax.xml.transform.Source;
import javax.xml.transform.stream.StreamSource;
import javax.xml.transform.stream.StreamResult;

/*
* This sample applies the todo.xsl stylesheet to the
* todo.xml XML document, and returns the transformation
* output (HTML) to the client browser.
*
* IMPORTANT: For this to work, you must place todo.xsl and todo.xml
* in the servlet root directory for documents.
*
*/

public class exp extends HttpServlet {

public void init(ServletConfig config) throws ServletException
{
super.init(config);
}

public void doGet (HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException
{
// Output goes in the response stream.
// The servlet returns HTML.
response.setContentType("text/html");

PrintWriter out = response.getWriter();

try
{
TransformerFactory tFactory = TransformerFactory.newInstance();
// Get the XML input document and the stylesheet.

//Source xmlSource = new StreamSource(new URL("http://www.bbc.co.uk/syndication/feeds/news/ukfs_news/world/rss091.xml").openStream());
Source xmlSource1 = new StreamSource(new URL("http://www.rediff.com/rss/usrss.xml").openStream());
Source xmlSource2 = new StreamSource(new URL("http://www.rediff.com/rss/newsrss.xml").openStream());
Source xslSource = new StreamSource(new URL("http://www.cs.odu.edu/~vsripada/cs695/classwork/xslt/getrss.xsl").openStream());
Source xslSource1 = new StreamSource(new URL("http://www.cs.odu.edu/~vsripada/cs695/classwork/xslt/getrss1.xsl").openStream());

// Generate the transformer.
Transformer transformer = tFactory.newTransformer(xslSource);
Transformer transformer1 = tFactory.newTransformer(xslSource1);

// Perform the transformation, sending the output to the response.
// transformer.transform(xmlSource, new StreamResult(out));
transformer.transform(xmlSource1, new StreamResult(out));
transformer1.transform(xmlSource2, new StreamResult(out));
}
catch (Exception e)
{
out.write(e.getMessage());
e.printStackTrace(out);
}

// out.println("<html><head></head><body><h1>Test</h1></body></html>");
out.close();
}

}

the prgm is running fine but i want to make some changes in the xsl file .....the xsl file is parsing the rss file and presents user ...the working version of the program is avilable at

URL

the xsl file source is


<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:dc="http://purl.org/dc/elements/1.1/" version="1.0">

<xsl

utput method="html"/>

<xsl:template match="/">
<html><head><title>Today's Headlines</title></head>
<style><xsl:comment>

p { font-size: 8pt;
font-family: arial,helvetica; }

h1 { font-size: 12pt;
font-family: arial,helvetica;
font-weight: bold; }

a:link { color:blue;
font-weight: bold;
text-decoration: none; }

a:visited { font-weight: bold;
color: darkblue;
text-decoration: none; }

</xsl:comment></style>
<body>
<form method='get' action="TempClient">
<input type="text" name="code" size="5"/>
<input type="submit" value="Get Temp"/>
</form>
<xsl:apply-templates/>
</body></html>
</xsl:template>

<xsl:template match="channel">
<xsl:apply-templates select="document(@src)"/>
</xsl:template>


<xsl:template name="a-element">
<xsl:element name="a">
<xsl:attribute name="href">
<xsl:apply-templates select="*[local-name()='link']"/>
</xsl:attribute>
<xsl:attribute name="title">
<xsl:apply-templates select="*[local-name()='description']"/>
</xsl:attribute>
<xsl:value-of select="*[local-name()='title']"/>
</xsl:element>
</xsl:template>


<xsl:template match="*[local-name()='channel']">
<xsl:element name="h1">
<xsl:call-template name="a-element"/>
</xsl:element>

<xsl:apply-templates select="*[local-name()='item']"/>
</xsl:template>


<xsl:template match="*[local-name()='item']">
<xsl:element name="p">
<xsl:call-template name="a-element"/>
<xsl:text> </xsl:text>
<xsl:if test="dc:date"> 
<xsl:text>( </xsl:text>
<xsl:value-of select="dc:date"/>
<xsl:text>) </xsl:text>
</xsl:if>
</xsl:element>
</xsl:template>
</xsl:stylesheet>

i would like to modify the style sheet so that i can present to user in a tabular or in some good format.....i've problem adding table here in the style sheet

.....

anykind of help appreciated.....

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