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#1
October 13th, 2004, 03:39 PM
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Quick XPath/Dom4J question.
I am able to retrieve date from an XML file using XPath and turn them into a org.dom4j.Element. However, when I print the full path of the Element by using Element.getPath(), I don't get all the info I need.
What I need is this: Path = /aaa/bbb=567/ccc=123/ddd But what I get from getPath() is this: Path = /aaa/bbb/ccc/ddd Is there any way to get the attributes in the path? Thanks.
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#2
October 15th, 2004, 03:45 PM
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Anyone?
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#3
October 17th, 2004, 02:00 PM
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I don't think there's something built-in as you want it, but it's not that hard (if I understand you right):
Code:
string GetFullyQualifiedXPath(Element ele) {
string fullPath = "";
Element current = ele;
do {
strung currentPath += "*[local-name() = '" + current.LocalName + "' && namespace-uri() = '" + current.NamespaceUri + "'";
foreach (Attribute attr in ele.Attributes) {
currentPath += " && @" + attr.Name + " = '" + attr.Value + "'";
}
currentPath += "]";
fullPath = currentPath + "/" + fullPath;
current = current.ParentNode;
} while (current != null);
return fullPath;
}
Above code won't compile in java, it's just some pseudo code. It will generate a full qualified x-path to any element in your document. Example: Code:
<Document> <Root> <Child Key1="Value" /> </Root> </Document> For example, a call of GetFullyQualifiedXPath for Node "Child" will return: /*[local-name() = 'Document' && namespace-uri() = '']/*[local-name() = 'Root' && namespace-uri() = '']/*[local-name() = 'Child' && namespace-uri() = '' && @Key1 = 'Value']
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