travelling through all different nodes...with same order

dear all
can anyone help me this pls...thank u with regards - niha..
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xml structure
<root>
<GeneralText>
<nodeA>some text A</nodeA>
<nodeB>some text BBBB</nodeB>
<nodeA>AAAAsome text A</nodeA>
<nodeB>BBBB</nodeB>
<nodeA>AAAAA</nodeA>
<nodeB>textBBBB</nodeB>
<nodeB>tBBBextBBBB</nodeB>

</GeneralText>
<GeneralText>
<nodeA>A</nodeA>
<nodeB>B</nodeB>
<nodeA>AAAAsome text A</nodeA>
<nodeB>BBBB</nodeB>

<nodeA>AAA</nodeA>
<nodeB>tetBBBB</nodeB>
<nodeB>tBBBextBBBB</nodeB>

</GeneralText>
</root>




------------------

i would like to in my xsl -algorithm

1. For each <GeneralText>
2. travel through the nodes ...same order such as <nodeA>,<nodeB>,<nodeA>,<nodeB>,>,<nodeA>,<nodeB>,<nodeB>

3. if node name is = nodeA
{ perfom some operation ....}
if node name is = node B
{ perfom operations B...}

4. if all nodes in GeneralText complete/just before end of for loop - { print General text completed...}
------------
xsl program

<xsl:for-each select="GeneralText"> ----- 1
<xsl:for-each select="*"> 2. -- passing/travellign through all nodes......here could someone suggest - how to pass through all......in same order - if i put <xsl:for-each select="nodeA"> i can travel only nodeA - but i want pass through all ---??? so pls suggest this :: step 2


in this step 3:: here i have to test ..the node node name and perform operation according to the name
<xsl:if test="name(.)='nodeA'">
{ perfom some operation ....}
<.xsl:if>

<xsl:if test="name(.)='nodeB'">
{ perfom operations B...}
<.xsl:if>


</xsl:for-each>
<b>General Text Completed</b> ------ 4
</xsl:for-each>

-------------

i wish someone help me in step 2 and step 3 thank u ever so much - with regards - niha

echo - thank u i will look into that

with regards
niha