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Old June 10th, 2003, 03:55 PM
jmeadows111 jmeadows111 is offline
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XML newbie -- handling one element differently

This is probably obvious, but I cannot get it to work, after having tried various approaches. The following stylesheet will bascilly copy everything from the source to the target. What I need to do is way to trap if the current node is a table tag (I am transforming xhtml) and pass that off to a separate section of the xsl document. I know the name() function will get me the name of the current node, but I can't seem to get the test working properly. Thanks in advance for any assistance to a struggling newcomer!

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/ | @* | node()">

<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>


</xsl:template>
</xsl:stylesheet>

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Old June 11th, 2003, 07:30 PM
jmeadows111 jmeadows111 is offline
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Thanks very much for your help -- it is most appreciated!!

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