i have problem with it
i have XML1 and with XSL1 (PI) i want to have fictive (in browser) XML2 which calls XSL2 which make HTML
simple as that,but i have problem with viewing in browser
so,code is here and i dont know why browsers doesnt show it when i directly call XML1 (http://www.some-domain.com/xml1.xml)
XML1 (xml1.xml)
Code:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [
<!ENTITY nbsp "*">
]><?xml-stylesheet href="xsl1.xsl" type="text/xsl"?>
<element>text1</element>
XSL1 (xsl1.xsl)
Code:
<?xml version='1.0'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method='xml' version='1.0'/>
<xsl:template match="/">
<xsl:processing-instruction name="xml-stylesheet">
<xsl:text>type="text/xsl" href="xsl2.xsl"</xsl:text>
</xsl:processing-instruction>
<xsl:apply-templates />
</xsl:template>
<xsl:template match="@* | *">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template></xsl:stylesheet>
output from XSL1 should be (and i think is)
Code:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [
<!ENTITY nbsp "*">
]><?xml-stylesheet href="xsl2.xsl" type="text/xsl"?>
<element>text1</element>
XSL2 (xsl2.xsl)
Code:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html"/>
<xsl:template match="/">
<HTML>
<xsl:apply-templates select="."/>
</HTML>
</xsl:template>
</xsl:stylesheet>
i try it with red,and without red,but there is no result,accept first transformation (XML2),but that XML2 (fictive in browser) doesnt call XSL2 (xsl2.xsl)
any one could help,pls?
i dont see where i mistake or what is wrong
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March 22nd, 2008, 11:42 AM
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