XPATH query help ??

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May 20th, 2004, 04:32 AM

Johnboy_Endy

Registered User

Join Date: May 2004

Posts: 1

Time spent in forums: < 1 sec
Reputation Power: 0

XPATH query help ??

Hi,

I am wanting to query the following XMl document with a user id, using XPATH, and return a list of the section type's.

eg. if i submitted john i would get General and if i submitted Bill i would get General Author.

I think this has something to do with parent:: but cant work it out.

Hopefully some of you guys might have an idea, save me a few days of pain!!!!

Thanks

<menu>

<section type="General">
<users>
<userid>john</userid>
<userid>Bill</userid>
</users>
<link href="home.aspx">
<Text>Home</Text>
</link>
<link href="navigation.aspx">
<Text>Navigation</Text>
</link>
</section>

<section type="Author">
<users>
<userid>Frank</userid>
<userid>Bill</userid>
</users>
<link href="authors.aspx">
<Text>View Author</Text>
</link>
<link href="authNews.aspx">
<Text>Author News</Text>
</link>
</section>
</menu>

May 21st, 2004, 02:23 AM

fpmurphy

Contributing User

Join Date: Dec 2003

Location: USA

Posts: 282

Time spent in forums: 1 Day 2 h 30 m 42 sec
Reputation Power: 6

The following stylesheet demonstrates how to find the section types for a particular userid.

Code:

<?xml version='1.0'?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                version="1.0">

<!-- the selected user -->
<xsl:variable name="user" select="'Bill'" />

<xsl:template match="/">
   <xsl:call-template name="find" >
      <xsl:with-param name="user" select="$user" />
   </xsl:call-template>
</xsl:template>

<xsl:template name="find" >
   <xsl:param name="user" />
   User: <xsl:value-of select="$user" />
   <xsl:for-each select="//section[//userid=$user]/@type" >
       Section: <xsl:value-of select="."/>
   </xsl:for-each>
</xsl:template>

</xsl:stylesheet>

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