August 26th, 2004, 08:34 AM
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Join Date: Aug 2004
Posts: 5
Time spent in forums: 42 m 26 sec
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XSL: Accessing previous node element
XML:
Code:
<articles>
<article>
<ArticleID>756</ArticleID>
<ArticleDate>16/07/2004</ArticleDate>
<Expiry>01/01/2012</Expiry>
</article>
<article>
<ArticleID>755</ArticleID>
<ArticleDate>11/06/2003</ArticleDate>
<Expiry>01/01/2012</Expiry>
</article>
</articles>
XSL:
Code:
<xsl:template match="article">
<xsl:param name="currentyear" select="substring(ArticleDate, 7, 4)"/>
<xsl:choose>
<xsl:when test="position()=1">
<tr><td><xsl:value-of select="$currentyear"/></td></tr>
</xsl:when>
<xsl:otherwise>
<xsl:if test="(position()-1)substring(ArticleDate, 7, 3)!=$newyear">
<tr>
<td><xsl:value-of select="$newyear"/></td>
</tr>
</xsl:if>
</xsl:otherwise>
</xsl:choose>
<tr><td valign="top"><xsl:apply-templates select="files"/>
</td></tr>
</xsl:template>
I'm trying to print a list of articles ordered by descending date and grouped by year. So when the year changes from 2004 to 2003, print the year once, list the rest of the 2003 articles and so on (2002,2001).
i.e.
2004
article1
article2
article3
2003
article4
article5
2002
article6
The crux of the problem is this line
Code:
<xsl:if test="(position()-1)substring(ArticleDate, 7, 3)!=$newyear">
I want to access the previous article's date and the year within it and test it against the current year.
Cheers,
Mick
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