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#1
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Hello !
I have a problem with XSL : I want to know the name of the parent-node, for example : <xsl:if test="name(parent)='foobar'">...</xsl:if> But it doesn't work. I tried parent, name, local-name, foobar, 'foobar', xsl:when, ... Nothing works properly. I hope, someone helps me !!! CU, d0n |
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#2
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It was so easy... It is :
<xsl:if test="parent::foobar">...</xsl:if> Now I gave myself the answer !! |
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| Viewing: Dev Shed Forums > Programming Languages - More > XML Programming > XSL-Problem |
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