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#1
July 3rd, 2003, 10:32 AM
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XSL Question Please Help Sorry I'm still learning
I would hope anyone can help me understand a certain problem I am currently having with a small piece of code. I would be very grateful if anyone could give me some ideas on how I could structure my XSL template to produce an output similar to the following table given the attached Test.xml source. I seem to be using for-each and the priority attribute but cant pinpoint where to place it correctly.
View the Test.xml source at : Test.xml Required result in table format is : ASXCode Company Name Company Statistics/Interim Dates Annual Balance Sheet/Cash RWS Rothbury Wines Limited -- 99,000 OCO Oriel Communications Limited 12/2002 97,065 NRL Newland Resources Limited 12/2002 95,143 MCL M2M Corporation Limited 12/2002 95,033 SUP Supersorb Environment NL 12/2002 94,328
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#2
July 3rd, 2003, 12:04 PM
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Perhaps someting like:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl  utput method="html" /><xsl:template match="/"> <HTML><HEAD><TITLE>Ausgabe von test:</TITLE> </HEAD> <BODY> <TABLE border="1"> <xsl:apply-templates /> </TABLE> </BODY> </HTML> </xsl:template> <xsl:template match="ResultSet"> <TR> <xsl:for-each select="Metadata/Column"> <TD><B><xsl:value-of select="@label"/></B></TD> </xsl:for-each> </TR> <xsl:apply-templates/> </xsl:template> <xsl:template match="Record"> <TR> <TD><xsl:value-of select="./Column[1]"/></TD> <TD><xsl:value-of select="./Column[2]"/></TD> <TD><xsl:value-of select="./Column[3]"/></TD> <TD><xsl:value-of select="./Column[4]"/></TD> <TD><xsl:value-of select="./Column[5]"/></TD> <TD><xsl:value-of select="./Column[6]"/></TD> <TD><xsl:value-of select="./Column[7]"/></TD> </TR> <xsl:value-of select="./Column[1]"/> </xsl:template> </xsl:stylesheet> may help you.
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