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#1
February 6th, 2002, 03:07 AM
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XSL questions
Hello,
I dont know how to make a number list based on some condition in XSL. For example, it prints the Filename only when the 'FileStatus = 1' eg. <xsl:for-each select="./Files/File"> <xsl:if test="./FileStatus = 1"> No. <xsl:value-of select="position()"/> Filename: <xsl:value-of select="./Filename"/> </xsl:if> </xsl:for-each> The above codes will print No.1 Filename: FileA.txt No.5 Filename: FileB.txt and that is not my desired result. I want the 'No.' print in the order 1,2,3,4 .... eg. No.1 Filename: FileA.txt No.2 Filename: FileB.txt Anyone got some solution here? Thanks.
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#2
February 7th, 2002, 04:21 AM
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<xsl:variable name="print" select="Files/File[FileStatus = 1]"/>
<xsl:for-each select="$print"> No. <xsl:value-of select="position()"/> Filename: <xsl:value-of select="./Filename"/> </xsl:for-each> 
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