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#1
September 19th, 2004, 01:27 PM
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XSLT - document function, string+$var+string...?
I have a series of XML files that represent courses. They look something like the simplified version below, but each files root node will have a different department attribute:
Code:
<course id="a1" department="art"> <name>My Course</name> <description>This is a description of my course.</description> </course> Now I want to use the document function to load the department XML file so that I can provide additional information in my output. The URI of this file is made up like so: Code:
D:/departments/variableName/index.xml I presumed I could just concat a string, the variable, and another string and pass that as the argument to the document function, but it does'nt work (see code below). Code:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<!-- Global Variables -->
<xsl:variable name="myVar" select="/course/@department" />
<xsl:variable name="departmentOverview" select="document('../../departments/'+$myVar+'/index.xml')" />
</xsl:stylesheet>
I have also tried a bunch of bizarre method involving switching variables around, and converting them to strings using the string function, but none of them worked. As anyone got any suggestions? I'm stumped.  Thanks for any help,
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#2
September 19th, 2004, 03:03 PM
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Oh it's been a while since I've played with XSL, but try this:
Code:
<xsl:variable name="departmentOverview" select="document('../../departments/{/course/@department}/index.xml')" />
__________________
# Jeremy Explain your problem instead of asking how to do what you decided was the solution.
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#3
September 19th, 2004, 03:32 PM
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Quote:
Nope that didn't work. I tried to test if it was working (as explained here ), but from what I can tell the curly brackets are just being interpreted as part of the string. Thanks for the suggestion though.
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#4
September 19th, 2004, 05:28 PM
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Do you need to create the variable? If you use the value of departmentOverview directly as an attribute in the resulting HTML, it should work. What I mean:
Code:
<xsl:stylesheet ...>
<a href="../../departments/{/course/@department}/index.xml">Your link's text.</a>
</xsl:stylesheet>
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#5
September 19th, 2004, 07:21 PM
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Quote:
I need to load the department XML file that the current course XML file is related to so that I can output extra information, so the above won't work. Simply put what I am trying is this (but where the URI of the XML file is determined by the department attribute of the source trees root node): Code:
<!-- Global Variables -->
<xsl:variable name="departmentOverview" select="document('D:/root node's department attribute/index.xml')" />
<xsl:template match="/">
The name of the department that this course belongs to is: <xsl:value-of select="$departmentOverview/department/name" />.
The name of the coordinator of the department that this course belongs to is: <xsl:value=of select="$departmentOverview/department/coordinator" />
</xsl:template>.
Would result in this output: Quote:
Thanks for the help. 
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#6
September 20th, 2004, 11:50 AM
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Hi, is it actually possible to do what you're trying to do? I'm curious, because I'd LOVE to do something similar this way -- I had to use javascript and perform the translations in an html page...
Question -- why not just link the stylesheet from the XML data files? -- each file will need to include the line: <?xml-stylesheet type="text/xsl" href="template.xsl"?>
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#7
September 20th, 2004, 07:58 PM
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I don't if it is possible, thats why I asked. I would presume it is possible as it isn't exactly anything complex that I am trying here, simply just adding a variable to a string in an XPath expression.
I suppose I could create several stylesheets one for each department, but the idea was to just have the one stylesheet and keep everything nice and neat.
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